10p^2-2p-36=0

Solution for 10p^2-2p-36=0 equation:

10p^2-2p-36=0

a = 10; b = -2; c = -36;
Δ = b2-4ac
Δ = -22-4·10·(-36)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-38}{2*10}=\frac{-36}{20}
=-1+4/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+38}{2*10}=\frac{40}{20}
=2
$